Ideal Simple Rankine Cycle

Cycle data

Known properties
  • Temperature at the boiler outlet 250 °C;
  • Pressure before turbine 1000 kPa;
  • Pressure after turbine 10 kPa.
Input code
using CycleSolver

@solve begin
    st3.T = 250 + 273
    st3.p = 1000
    st1.p = 10

    newCycle[]
        pump(st1, st2)
        boiler(st2, st3)
        turbine(st3, st4)
        condenser(st4, st1) 
end

PrintResults()

Output:

1- CYCLE [water]

State
Name		 T [K] P [kPa] h [kJ/kg] s [kJ/kg.K] x ṁ [kg/s] Mass-flux
fraction
st1 318.956 10.0 191.806 0.6492 0.0 1.0
st2 318.989 1000.0 192.806 0.6492 1.0
st3 523.0 1000.0 2942.79 6.9258 1.0
st4 318.956 10.0 2193.78 6.9258 0.8369 1.0

Cycle Properties:

Total Component Value
qin
Q̇in		 2749.9849 kJ/kg
0.0 kW		 boiler:
st2 >> st3		 2749.9849 kJ/kg
qout
Q̇out		 2001.9783 kJ/kg
0.0 kW		 condenser:
st4 >> st1		 2001.9783 kJ/kg
win
Ẇin		 1.0 kJ/kg
0.0 kW		 pump:
st1 >> st2		 1.0 kJ/kg
wout
Ẇout		 749.0066 kJ/kg
0.0 kW		 turbine:
st3 >> st4		 749.0066 kJ/kg

Thermal efficiency (n) = 27.2004 %