Refrigeration cycle

Cycle data

Known properties
  • Refrigerant-134a is used as working fluid;
  • Pressure at the compressor inlet 300 kPa;
  • Pressure at the compressor outlet 1500 kPa;
  • The compressor has an isentropic efficiency of 90%.
Input code
using CycleSolver

@solve begin
    st1.p = 300
    st2.p = 1500
    newRefrigerationCycle[R134a]
        compressor(st1, st2, 90)
        condenser(st2, st3)
        expansion_valve(st3, st4)
        evaporator(st4, st1)
end

PrintResults()

Output:

1- REFRIGERATION CYCLE [R134a]

State
Name
T [K] P [kPa] h [kJ/kg] s [kJ/kg.K] x ṁ [kg/s] Mass-flux
fraction
st1 273.822 300.0 250.851 0.9311 1.0 1.0
st2 337.097 1500.0 288.025 0.9422 1.0
st3 328.383 1500.0 131.695 0.4665 0.0 1.0
st4 273.822 300.0 131.695 0.4959 0.3985 1.0

Cycle Properties:

Total Component Value
qin
Q̇in
119.1562 kJ/kg
0.0 kW
evaporator:
st4 >> st1
119.1562 kJ/kg
qout
Q̇out
156.3305 kJ/kg
0.0 kW
condenser:
st2 >> st3
156.3305 kJ/kg
win
Ẇin
37.1743 kJ/kg
0.0 kW
compressor:
st1 >> st2
37.1743 kJ/kg
wout
Ẇout
0.0 kJ/kg
0.0 kW

Coefficient of performance (COP) = 3.2053