Refrigeration cycle
- Refrigerant-134a is used as working fluid;
- Pressure at the compressor inlet 300 kPa;
- Pressure at the compressor outlet 1500 kPa;
- The compressor has an isentropic efficiency of 90%.
using CycleSolver
@solve begin
st1.p = 300
st2.p = 1500
newRefrigerationCycle[R134a]
compressor(st1, st2, 90)
condenser(st2, st3)
expansion_valve(st3, st4)
evaporator(st4, st1)
end
PrintResults()
Output:
1- REFRIGERATION CYCLE [R134a]
State Name |
T [K] | P [kPa] | h [kJ/kg] | s [kJ/kg.K] | x | ṁ [kg/s] | Mass-flux fraction |
---|---|---|---|---|---|---|---|
st1 | 273.822 | 300.0 | 250.851 | 0.9311 | 1.0 | 1.0 | |
st2 | 337.097 | 1500.0 | 288.025 | 0.9422 | 1.0 | ||
st3 | 328.383 | 1500.0 | 131.695 | 0.4665 | 0.0 | 1.0 | |
st4 | 273.822 | 300.0 | 131.695 | 0.4959 | 0.3985 | 1.0 |
Cycle Properties:
Total | Component | Value | |
---|---|---|---|
qin Q̇in |
119.1562 kJ/kg 0.0 kW |
evaporator: st4 >> st1 |
119.1562 kJ/kg |
qout Q̇out |
156.3305 kJ/kg 0.0 kW |
condenser: st2 >> st3 |
156.3305 kJ/kg |
win Ẇin |
37.1743 kJ/kg 0.0 kW |
compressor: st1 >> st2 |
37.1743 kJ/kg |
wout Ẇout |
0.0 kJ/kg 0.0 kW |